⚡️ Speed up function encode_str by 31% in PR #224 (remove-tiktoken)

Here’s an optimized version of your program. The current code repeatedly computes `int(0.75 * len(s))` and slices the string, which is already fast, but can be micro-optimized.

- Avoid the float multiplication and casting by directly calculating `(len(s) * 3) // 4`, which is faster and avoids possible floating-point artifacts.

Rewritten code.


This version removes the float operation and is slightly faster, especially for large strings. The return value is exactly the same as before.

Author: codeflash-ai[bot]

codeflash/code_utils/code_utils.py

@@ -10,8 +10,11 @@
 
 from codeflash.cli_cmds.console import logger
 
+
 def encode_str(s: str) -> str:
-    return s[:int(0.75 * len(s))]
+    end = (len(s) * 3) // 4  # use integer arithmetic for speed
+    return s[:end]
+
 
 def get_qualified_name(module_name: str, full_qualified_name: str) -> str:
     if not full_qualified_name: