From cab140f466f604916be746547f80c3d54e4da95b Mon Sep 17 00:00:00 2001
From: "codeflash-ai[bot]"
 <148906541+codeflash-ai[bot]@users.noreply.github.com>
Date: Wed, 18 Jun 2025 22:34:33 +0000
Subject: [PATCH] =?UTF-8?q?=E2=9A=A1=EF=B8=8F=20Speed=20up=20function=20`s?=
 =?UTF-8?q?orter`=20by=20176,844%=20Here=E2=80=99s=20a=20high-performance?=
 =?UTF-8?q?=20rewrite=20of=20your=20function.=20Your=20original=20code=20u?=
 =?UTF-8?q?ses=20a=20naive=20**bubble=20sort**=20(O(n=C2=B2)),=20which=20i?=
 =?UTF-8?q?s=20extremely=20slow=20for=20large=20lists.=20Python=E2=80=99s?=
 =?UTF-8?q?=20built-in=20`list.sort()`=20uses=20Timsort=20(**O(n=20log=20n?=
 =?UTF-8?q?)**=20in=20practice),=20which=20is=20much=20faster=20and=20opti?=
 =?UTF-8?q?mized=20in=20C.=20Also,=20`list.sort()`=20is=20in-place,=20just?=
 =?UTF-8?q?=20like=20your=20version.?=
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**Optimized code:**


**Explanation of changes:**
- Replaced the double for-loop with the built-in `.sort()` for optimal speed and reduced memory usage.
- Kept all function comments/outputs unchanged, except where the sort logic is optimized.

**Result:**
- Empirically, this will be **orders of magnitude faster** and also reduces the interpreter overhead.
- Output and return are exactly the same as your original function.

If you must provide your own sort algorithm (instead of using `sort()`), consider using a faster implementation like **quicksort** or **heapsort**. But in production Python, **the built-in sort is always preferred for performance**.
---
 code_to_optimize/bubble_sort.py | 7 +------
 1 file changed, 1 insertion(+), 6 deletions(-)

diff --git a/code_to_optimize/bubble_sort.py b/code_to_optimize/bubble_sort.py
index 9e97f63a0..809c5cb8f 100644
--- a/code_to_optimize/bubble_sort.py
+++ b/code_to_optimize/bubble_sort.py
@@ -1,10 +1,5 @@
 def sorter(arr):
     print("codeflash stdout: Sorting list")
-    for i in range(len(arr)):
-        for j in range(len(arr) - 1):
-            if arr[j] > arr[j + 1]:
-                temp = arr[j]
-                arr[j] = arr[j + 1]
-                arr[j + 1] = temp
+    arr.sort()  # much faster built-in sort (Timsort, O(n log n))
     print(f"result: {arr}")
     return arr