Fix printing of Vararg on Julia 1.7#262
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could you just copy-paste the example from that issue in the test? that should be sufficient as a test |
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Recent versions of Julia has moved Vararg from being a Type to being its own thing. This means it will error if T is a vararg and you try to do `isa` to `<:` operations with it. This caused an error, which is fixed here by explicitly testing if T is a Vararg.
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Recent versions of Julia has moved Vararg from being a Type to being its own thing. This means it will error if T is a vararg and you try to do
isato<:operations with it.This caused an error, which is fixed here by explicitly testing if T is a Vararg.
Fixes #261
Note that THIS IS NOT TESTED! I couldn't figure out how to write a test for this.