fix wildcard handling

JList is initialized with 0 or 1 arguments. The original is this:
        if (arguments.length === 1) {
            sequence.push(arguments[0]);
        }
If an argument is passed, it is added. The new code mimics this.

The second issue is in the wildard handling. In the list case, arrays
need to be flattended. The issue comes from the unnecessary handling of
maps. Like scalar types, those simply need to be added to the result

Author: aeberhart

src/main/java/com/dashjoin/jsonata/Jsonata.java

@@ -723,9 +723,6 @@ Object evaluateWildcard(Symbol expr, Object input) {
                 if((value instanceof List)) {
                     value = flatten(value, null);
                     results = (List)Functions.append(results, value);
-                } else if (value instanceof Map) {
-                // Call recursively do decompose the map
-                results.addAll((List)evaluateWildcard(expr, value));
                 } else {
                     results.add(value);
                 }

src/main/java/com/dashjoin/jsonata/Utils.java

@@ -79,11 +79,7 @@ public static List<Object> createSequence(Object el) {
         JList<Object> sequence = new JList<>();
         sequence.sequence = true;
         if (el!=NONE) {
-            if (el instanceof List && ((List)el).size()==1)
-                sequence.add(((List)el).get(0));
-            else
-            // This case does NOT exist in Javascript! Why?
-                sequence.add(el);
+            sequence.add(el);
         }
         return sequence;
     }

src/test/java/com/dashjoin/jsonata/ArrayTest.java

@@ -49,14 +49,12 @@ public void testSortNull() {
     Assertions.assertEquals(Arrays.asList(Map.of("x", 2), Map.of("x", 1)), expr.evaluate(null));
   }
 
-  @Disabled
   @Test
   public void testWildcard() {
     Jsonata expr = jsonata("*");
     Assertions.assertEquals(Map.of("x", 1), expr.evaluate(List.of(Map.of("x", 1))));
   }
 
-  @Disabled
   @Test
   public void testWildcardFilter() {
     Object value1 = Map.of("value", Map.of("Name", "Cell1", "Product", "Product1"));