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bit_inversion_count.cpp
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63 lines (59 loc) · 1.25 KB
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#include <bits/stdc++.h>
using namespace std;
int getsum(vector<int>& BIT,int x)
{ int sum=0;
while(x>0)
{
sum+=BIT[x];
x-=(x&(-x));
}
return sum;
}
void update(vector<int>& BIT,int val,int x)
{
while(x<BIT.size())
{
BIT[x]+=val;
x+=(x&(-x));
}
}
int countInversions(vector<int> &A) {
int maxi=INT_MIN;
vector<int> B,c(A.size());
for(int i=0;i<A.size();i++)
B.push_back(A[i]);
sort(B.begin(),B.end());
for(int i=0;i<A.size();i++)
{
int idx=lower_bound(B.begin(),B.end(),A[i])-B.begin();
c[i]=idx+1;
}
for(int i=0;i<c.size();i++)
if(maxi<c[i])
maxi=c[i];
vector<int>BIT(maxi+1,0);
int count=0;
for(int i=0;i<A.size();i++)
{
update(BIT,1,c[i]);
int a=getsum(BIT,BIT.size()-1);
int b=getsum(BIT,c[i]);
//cout<<A[i]<<" "<<a<<" "<<b<<"\n";
count+=(a-b);
}
return count;
}
int main() {
//int arr[] = {6,2,1,0,5,4};
//int n = sizeof(arr)/sizeof(int);
vector<int> A;
int n;
cin>>n;
for(int i=0;i<n;i++)
{
int a;
cin>>a;
A.push_back(a);
}
cout<<countInversions(A)<<endl;
}