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problem_005_00.py
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169 lines (134 loc) · 4.29 KB
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##Smallest multiple
##Problem 5
##2520 is the smallest number that can be divided by each of the numbers
##from 1 to 10 without any remainder.
##
##What is the smallest positive number that is evenly divisible by all
##of the numbers from 1 to 20?
import numpy as np
import time
def smallestnumber(Nmax):
# find the list of prime numbers in range(Nmax)
listprimes2ton = primesfrom2to(Nmax)
numbers = np.arange(2,Nmax, dtype=np.float64)
maxnumber = int(np.prod(numbers))
print(maxnumber)
for i in listprimes2ton:
test_ar = np.ones(len(numbers),dtype=bool)
print(i,test_ar)
print(maxnumber % i ==0)
print(numbers)
print(maxnumber % numbers)
print((maxnumber % numbers == 0).all())
while maxnumber % i == 0 and ((maxnumber/i) % numbers == 0).all():
maxnumber = maxnumber / i
print(maxnumber, i)
## if maxnumber % i == 0:
## nmaxnumber = int(maxnumber/i)
## print(nmaxnumber, maxnumber, i)
## test_ar = (nmaxnumber % numbers == 0)
## print(test_ar)
## while test_ar.all():
## print(test_ar)
## nmaxnumber = maxnumber/i
## print(nmaxnumber, maxnumber, i)
## test_ar = (nmaxnumber % numbers == 0)
## if test_ar.all():
## print(maxnumber)
## maxnumber = nmaxnumber
## print(maxnumber)
## minnumb = listprimes2ton.prod(axis=0)
## print(minnumb)
return maxnumber
def primesfrom2to(n):
""" Input n>=6, Returns a array of primes, 2 <= p < n """
sieve = np.ones(n/3 + (n%6==2), dtype=np.bool)
for i in range(1,int((n**0.5)/3+1)):
if sieve[i]:
k=3*i+1|1
sieve[ k*k/3 ::2*k] = False
sieve[k*(k-2*(i&1)+4)/3::2*k] = False
return np.r_[2,3,((3*np.nonzero(sieve)[0][1:]+1)|1)]
def calculatedivisors(maxlimit):
npdivisors = []
k = 0
while k == 0:
for i in range(2, int(maxlimit/2)):
if maxlimit % i == 0:
npd = np.ones(len(npdivisors), dtype=bool)
m = 0
try:
for j in npdivisors:
if i % j == 0:
npd[m] = False
break
m += 1
if npd.all():
npdivisors.append(i)
product = 1
for element in npdivisors:
product = element * product
if product == maxlimit:
k = 1
return npdivisors
except:
npdivisors.append(i)
print(npdivisors)
return npdivisors
def findpalind(Nmax):
list1 = []
for i in range(1, Nmax):
list1.append(i)
list1.reverse()
list2 = list1[:]
listpalind = set()
m = 0
while m == 0:
for i in list1:
for j in list2:
k = i * j
if str(k) == str(k)[::-1]:
## print("str(k) == str(k)[-1:1]", str(k), str(k)[::-1])
listpalind.add(k)
## print("appending ", k)
m = 1
## print(listpalind)
return listpalind
def isPal(s):
if len(s) <= 1:
return True
else:
return s == s[::-1]
def checkpals(Nmax):
val = 0
for i in range(Nmax,1,-1):
for j in range(Nmax,1,-1):
if isPal(str(i*j)) and i*j > val:
val = i*j
return val
def delbart(t,n):
if n > 0:
print(t)
if not (t%n):
if delbart(t, n-1):
return True
else:
return False
else:
return False
else:
return True
def main():
start = time.time()
## palind = findpalind(1000)
## print(max(palind))
## minnum = smallestnumber(20)
## print(minnum)
##
i = 20
while not delbart(i,20):
i +=20
print(i)
end = time.time()
print(end -start)
main()