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problem_008_00.py
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187 lines (145 loc) · 6.28 KB
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##Largest product in a series
##Problem 8
##Find the greatest product of five consecutive digits in the 1000-digit number.
##
##73167176531330624919225119674426574742355349194934
##96983520312774506326239578318016984801869478851843
##85861560789112949495459501737958331952853208805511
##12540698747158523863050715693290963295227443043557
##66896648950445244523161731856403098711121722383113
##62229893423380308135336276614282806444486645238749
##30358907296290491560440772390713810515859307960866
##70172427121883998797908792274921901699720888093776
##65727333001053367881220235421809751254540594752243
##52584907711670556013604839586446706324415722155397
##53697817977846174064955149290862569321978468622482
##83972241375657056057490261407972968652414535100474
##82166370484403199890008895243450658541227588666881
##16427171479924442928230863465674813919123162824586
##17866458359124566529476545682848912883142607690042
##24219022671055626321111109370544217506941658960408
##07198403850962455444362981230987879927244284909188
##84580156166097919133875499200524063689912560717606
##05886116467109405077541002256983155200055935729725
##71636269561882670428252483600823257530420752963450
import numpy as np
import time
def largestprod(string,length):
n = 1
for i in range(0,len(string)-(length)):
npd = np.arange(1,length+1)
for j in range(0, len(npd)):
npd[j] = int(string[i+j])
n = max(n,np.prod(npd))
return n
def smallestnumber(Nmax):
# find the list of prime numbers in range(Nmax)
listprimes2ton = primesfrom2to(Nmax)
# create an array for the factorization
valueeachprime = np.ones(len(listprimes2ton))
# create an array starting in number 2 ranging to Nmax, type float64
numbers = np.arange(2,Nmax, dtype=np.float64)
# factorize each number in the range. Update the factorization_array
for i in numbers:
while i not in listprimes2ton:
eachvalueprime = factorize(i, listprimes2ton)
for i in range(0,len(valueeachprime)):
valueeachprime[i] = max(valueeachprime[i],eachvalueprime[i])
valuearray = listprimes2ton**valueeachprime
# Calculate the least common multiple: with np.prod() I get an error or
# inconsistent results. I've tried several dtype = int, np.float64, but still get the error.
# So I use an alternative:
value = 1
for i in valuearray:
value = value * i
print(listprimes2ton)
print(valueeachprime)
return value
def factorize(n,listofprimes):
valueeachprime = np.zeros(len(listofprimes))
for i in range(1, len(listofprimes)):
while n >= listofprimes[i-1] and n % listofprimes[i-1] == 0:
n = n / listofprimes[i-1]
valueeachprime[i-1] = valueeachprime[i-1] + 1
return valueeachprime
def primesfrom2to(n):
""" Input n>=6, Returns a array of primes, 2 <= p < n """
sieve = np.ones(n/3 + (n%6==2), dtype=np.bool)
if n%2 == 0:
return "x2"
for i in range(1,int((n**0.5)/3+1)):
if sieve[i]:
k=3*i+1|1
sieve[ k*k/3 ::2*k] = False
sieve[k*(k-2*(i&1)+4)/3::2*k] = False
return np.r_[2,3,((3*np.nonzero(sieve)[0][1:]+1)|1)]
def calculatedivisors(maxlimit):
npdivisors = []
k = 0
while k == 0:
for i in range(2, int(maxlimit/2)):
if maxlimit % i == 0:
npd = np.ones(len(npdivisors), dtype=bool)
m = 0
try:
for j in npdivisors:
if i % j == 0:
npd[m] = False
break
m += 1
if npd.all():
npdivisors.append(i)
product = 1
for element in npdivisors:
product = element * product
if product == maxlimit:
k = 1
return npdivisors
except:
npdivisors.append(i)
print(npdivisors)
return npdivisors
def findpalind(Nmax):
list1 = []
for i in range(1, Nmax):
list1.append(i)
list1.reverse()
list2 = list1[:]
listpalind = set()
m = 0
while m == 0:
for i in list1:
for j in list2:
k = i * j
if str(k) == str(k)[::-1]:
## print("str(k) == str(k)[-1:1]", str(k), str(k)[::-1])
listpalind.add(k)
## print("appending ", k)
m = 1
## print(listpalind)
return listpalind
def isPal(s):
if len(s) <= 1:
return True
else:
return s == s[::-1]
def checkpals(Nmax):
val = 0
for i in range(Nmax,1,-1):
for j in range(Nmax,1,-1):
if isPal(str(i*j)) and i*j > val:
val = i*j
return val
def main():
start = time.time()
l = str(
7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450
)
print(largestprod(l,5))
## palind = findpalind(1000)
## print(max(palind))
## minnum = smallestnumber(40)
## print(minnum)
end = time.time()
print(end -start)
main()