Fix: Preserve original sequence type when slicing tuples in 'slice_val'.

Author: dylan-sutton-chavez

compiler/src/modules/vm/collections.rs

@@ -196,7 +196,10 @@ impl<'a> VM<'a> {
             }
             _ => return Err(VmErr::Type("slice".into())),
         };
-        self.heap.alloc(HeapObj::List(Rc::new(RefCell::new(result))))
+        match self.heap.get(obj) {
+            HeapObj::Tuple(_) => self.heap.alloc(HeapObj::Tuple(result)),
+            _                 => self.heap.alloc(HeapObj::List(Rc::new(RefCell::new(result)))),
+        }
     }
 
     /*

compiler/tests/cases/vm_cases.json

@@ -112,5 +112,7 @@
   {"src": "print(round(2.5))", "output": ["2"], "result": "None"},
   {"src": "print(list(zip([1,2],[3,4],[5,6])))", "output": ["[(1, 3, 5), (2, 4, 6)]"], "result": "None"},
   {"src": "a, b = [1, 2, 3]", "output": [], "result": "None", "error": "expected 2 values to unpack, got 3"},
-  {"src": "a, b, c = [1, 2]",  "output": [], "result": "None", "error": "expected 3 values to unpack, got 2"}
+  {"src": "a, b, c = [1, 2]",  "output": [], "result": "None", "error": "expected 3 values to unpack, got 2"},
+  {"src": "t = (1,2,3,4,5)\nprint(type(t[1:3]))","output": ["tuple"],"result": "None"},
+  {"src": "l = [1,2,3,4,5]\nprint(type(l[1:3]))","output": ["list"],"result": "None"}
 ]