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Copy pathmyscanner.c
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108 lines (86 loc) · 2.31 KB
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#include <stdio.h>
#include <time.h>
#include "values.h"
extern int yylex();
extern int yylineno;
extern char* yytext;
int main (void){
int ntoken, prevToken, expectedIndent, i;
int currentIndent = 0;
double start, end;
start=time(0);
ntoken = yylex();
while(ntoken){
switch (ntoken){
case 1:
//The Token matched to be a Keyword
printf( "Keyword (%s)\n", yytext);
prevToken = ntoken;
ntoken = yylex();
break;
case 2:
//The Token matched to be a literal
printf( "Literal (%s)\n", yytext);
prevToken = ntoken;
ntoken = yylex();
break;
case 3:
//The Token matched to be an operator
printf( "Operator (%s)\n", yytext);
prevToken = ntoken;
ntoken = yylex();
break;
case 4:
//The Token matched to be an identifier
printf( "Identifier (%s)\n", yytext);
prevToken = ntoken;
ntoken = yylex();
break;
case 5:
//The Token matched to be a delimeter
printf( "Delimiters (%s)\n", yytext);
prevToken = ntoken;
ntoken = yylex();
break;
case 6:
//The Token matched to be an Indent
++currentIndent;
prevToken = ntoken;
ntoken = yylex();
break;
case 7:
//The Token matched to be a NewLine
prevToken = ntoken;
ntoken = yylex();
if(!ntoken){
break;
}
printf( "NEWLINE\n");
//This line is needed because in the case of an indent following an indent the following conditional would be true.
if((expectedIndent > 0 && ntoken==6)||expectedIndent == 0){
}
//In a case where you are expecting an Indent and the following token is not an indent then you will go back, or dedent, the number of indents
else if(expectedIndent > 0 && ntoken!=6){
int temp = expectedIndent;
for(i=0; i < temp; i++){
printf("DEDENT\n");
expectedIndent--;
}
}
currentIndent = 0;
break;
default:
//The Token didn't match anything
printf("Syntax error in line %d\n", yylineno);
}
if(ntoken != 6 && prevToken == 6){
for(i=0; i<currentIndent; i++){
printf("INDENT \n");
}
expectedIndent = currentIndent;
}
}
end = time(0);
printf("%f\n",end-start);
return 0;
}