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15-SQL-Server-Preencher-Valores-Entre-Datas.sql
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71 lines (56 loc) · 1.53 KB
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COMO ESTÁ:
DATA SALARIO
01/01/2020 - 1.300,00
01/05/2020 - 1.500,00
01/11/2021 - 2.000,00
COMO DEVE FICAR:
DATA SALARIO
01/01/2020 - 1.300,00
01/02/2020 - 1.300,00
01/03/2020 - 1.300,00
01/04/2020 - 1.300,00
01/05/2020 - 1.500,00
01/06/2020 - 1.500,00
01/07/2020 - 1.500,00
01/08/2020 - 1.500,00
01/09/2020 - 1.500,00
01/10/2020 - 1.500,00
01/11/2021 - 2.000,00
/* 1. Disponibilizar os dados (Tabela Constante, Criar Tabela) */
SELECT [Data], Salario
INTO SALARIOS
FROM
(
VALUES
(CAST('01/01/2020' AS datetime),1300.00),
(CAST('01/05/2020' AS datetime),1500.00),
(CAST('01/11/2021' AS datetime),2000.00)
) TSALARIOS([Data], Salario)
/* 2. Identificar o registro posterior (LEAD) */
SELECT
[Data] AS Data_Inicial,
LEAD([Data]) OVER(Order by [Data]) AS Data_Final,
Salario
FROM SALARIOS
/* 3. Listar datas e relacionar os Salários (CTE, Hierarquia) */
DECLARE @start_date DATETIME = (SELECT MIN([Data]) FROM SALARIOS);
DECLARE @end_date DATETIME = (SELECT MAX([Data]) FROM SALARIOS);
WITH CALENDARIO AS (
-- Hierarquia
SELECT @start_date AS [Date], 1 AS [level]
UNION ALL
SELECT DATEADD(MONTH, 1, [Date]), [level] + 1
FROM CALENDARIO
WHERE [Date] < @end_date
), DATA_SALARIOS AS (
SELECT
[Data] AS Data_Inicial,
LEAD([Data]) OVER(Order by [Data]) AS Data_Final,
Salario
FROM SALARIOS
)
SELECT t1.[Date], t2.Salario
FROM CALENDARIO t1
JOIN DATA_SALARIOS t2
ON (t1.[Date] >= t2.Data_Inicial AND t1.[Date] < t2.Data_Final)
OR (t1.[Date] >= t2.Data_Inicial AND t2.Data_Final IS NULL)