Update 12.tex

Author: Paciic

src/chapters/6/sections/means_medians_modes_moments/problems/12.tex

@@ -30,8 +30,8 @@
     &= \frac{1}{n^2} \cdot n\sigma^2 + \frac{1}{n^2} \cdot (nc)^2 \\ 
     &= \frac{\sigma^2}{n} + c^2 \\ 
 \end{flalign*}
-Hence the bias of \(T_1\) is \[\frac{\sigma^2}{n} + c^2 - c^2 = \frac{\sigma^2}{n}\] 
-\\ \\
+Hence the bias of \(T_1\) is \[\frac{\sigma^2}{n} + c^2 - c^2 = \frac{\sigma^2}{n}\] \\
+
 Finding the bias of \(T_2\), we need to find \(\text{E}(T_2) - c^2\). \[ \text{E}(T_2) = \text{E}(\frac{1}{n}\sum_{j=1}^{n}{X}_j^2) \]
 By linearity of expectation,
 \begin{flalign*}