Chapter 1 - Problem 32, possible error in Case 3

The answer for Problem 32 Case 3, where j = 2 was given as $\frac{1}{3}$ but if the possibilities are listed, the answer comes out as $\frac{2}{3}$ as demonstrated in [this post](https://math.stackexchange.com/questions/2153507/probability-four-cards-face-down-two-are-red-two-are-black-aim-is-to-find-th)