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Day_4.Number Complement
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50 lines (40 loc) · 1.39 KB
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Problem Statement
Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation.
Example 1:
Input: 5
Output: 2
Explanation: The binary representation of 5 is 101 (no leading zero bits), and its complement is 010. So you need to output 2.
Example 2:
Input: 1
Output: 0
Explanation: The binary representation of 1 is 1 (no leading zero bits), and its complement is 0. So you need to output 0.
Note:
The given integer is guaranteed to fit within the range of a 32-bit signed integer.
You could assume no leading zero bit in the integer’s binary representation.
Soln
def findComplement(self, num: int) -> int:
def decimalToBinary(N):
res = 0
while N>=1:
temp = math.floor(math.log2(N))
res+=10**temp
N = N-2**temp
return res
def binaryToDecimal(N):
res = 0
count = 0
lst = list(str(N))
while lst:
temp = int(lst.pop())
if temp==1:
res+=2**count
count+=1
return res
def complement(num):
lst=[str(int(i) ^ 1) for i in str(num)]
p="".join(lst)
return p.lstrip('0')
p=decimalToBinary(num)
q=complement(p)
result=binaryToDecimal(q)
return result