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Python Basic and Advance Questions list - be ready to solve them

Agar question realted koi porblem hai to mujhe YouTube Discussion par puch sakte ho.

Note: Sabhi questions searial wise hain, to kosis karo ki inhe isi serial me solve karo. Good luck

Note: Sabhi answer usi sequence me hain jinme questions hai

String Questions:

  1. Find all occurrences of “USA” in given string ignoring the case

             inputString = "Welcome to USA. usa awesome, isn't it?"
         substring = "USA"
         tempString = inputString.lower()
         count = tempString.count(substring.lower())
         print("The USA count is:", count)

  2. Given a string, return the sum and average of the digits that appear in the string, ignoring all other characters

             import re

         inputStr = "English = 78 Science = 83 Math = 68 History = 65"
         markList = [int(num) for num in re.findall(r'\b\d+\b', inputStr)]
         totalMarks = 0
         for mark in markList:
           totalMarks+=mark

         percentage = totalMarks/len(markList)  
         print("Total Marks is:", totalMarks, "Percentage is ", percentage)

  3. Given an input string, count occurrences of all characters within a string

             inputStr = "pynativepynvepynative"
         countDict = dict()
         for char in inputStr:
           count = inputStr.count(char)
           countDict[char]=count
         print(countDict)

List questions:

  1. Given a Python list you should be able to display Python list in the following order

             aList = [100, 200, 300, 400, 500]
         aList = aList[::-1]
         print(aList)

  2. Concatenate two lists index-wise

     Note: We need to use list comprehension and zip() function as follows

         list1 = ["M", "na", "i", "Ke"] 
         list2 = ["y", "me", "s", "lly"]
         list3 = [i + j for i, j in zip(list1, list2)]
         print(list3)

  3. Given a Python list. Turn every item of a list into its square

             aList = [1, 2, 3, 4, 5, 6, 7]
         aList =  [x * x for x in aList]
         print(aList)

  4. Concatenate two lists in the following order

             list1 = ["Hello ", "take "]
         list2 = ["Dear", "Sir"]

         resList = [x+y for x in list1 for y in list2]
         print(resList)

  5. Given a two Python list. Iterate both lists simultaneously such that list1 should display item in original order and list2 in reverse order

             list1 = [10, 20, 30, 40]
         list2 = [100, 200, 300, 400]

         for x, y in zip(list1, list2[::-1]):
         print(x, y)

  6. Remove empty strings from the list of strings

     Note: We can use a filter() function to remove None type from the list


         list1 = ["Mike", "", "Emma", "Kelly", "", "Brad"]
         resList = list(filter(None, list1))
         print(resList)

  7. Add item 7000 after 6000 in the following Python List

     Note: Use the append() method

         list1 = [10, 20, [300, 400, [5000, 6000], 500], 30, 40]
         list1[2][2].append(7000)
         print(list1)

  8. Given a nested list extend it with adding sub list ["h", "i", "j"] in a such a way that it will look like the following list Given List:

             list1 = ["a", "b", ["c", ["d", "e", ["f", "g"], "k"], "l"], "m", "n"]
         subList = ["h", "i", "j"]

         list1[2][1][2].extend(subList)
         print(list1)

  9. Given a Python list, find value 20 in the list, and if it is present, replace it with 200. Only update the first occurrence of a value

             list1 = [5, 10, 15, 20, 25, 50, 20]

         index = list1.index(20)
         list1[index] = 200
         print(list1)

  10. Given a Python list, remove all occurrence of 20 from the list

     Note: Use the list comprehension

         list1 = [5, 20, 15, 20, 25, 50, 20]

         def removeValue(sampleList, val):
         return [value for value in sampleList if value != val]
         resList = removeValue(list1, 20)
         print(resList)

Python Tuple Exercise

  1. Reverse the following tuple

             aTuple = (10, 20, 30, 40, 50)
         aTuple = aTuple[::-1]
         print(aTuple)

  2. Access value 20 from the following tuple

             aTuple = ("Orange", [10, 20, 30], (5, 15, 25))
         print(aTuple[1][1])

  3. Create a tuple with single item 50

             aTuple = (50, )
         print(aTuple)

 Note: If you want to create a single value tuple, you must indicate it by adding a comma just before the closing parentheses.

  4. Unpack the following tuple into 4 variables

             aTuple = (10, 20, 30, 40)
         a, b, c, d = aTuple
         print(a)
         print(b)
         print(c)
         print(d)

  5. Swap the following two tuples

             tuple1 = (11, 22)
         tuple2 = (99, 88)
         tuple1, tuple2 = tuple2, tuple1
         print(tuple2)
         print(tuple1)

  6. Copy element 44 and 55 from the following tuple into a new tuple

             tuple1 = (11, 22, 33, 44, 55, 66)
         tuple2 = tuple1[3:-1]
         print(tuple2)

  7. Modify the first item (22) of a list inside a following tuple to 222

             tuple1 = (11, [22, 33], 44, 55)
         tuple1[1][0] = 222
         print(tuple1)

  8. Sort a tuple of tuples by 2nd item

             tuple1 = (('a', 23),('b', 37),('c', 11), ('d',29))
         tuple1 = tuple(sorted(list(tuple1), key=lambda x: x[1]))
         print(tuple1)

  9. Counts the number of occurrences of item 50 from a tuple

             tuple1 = (50, 10, 60, 70, 50)
         print(tuple1.count(50))

  10. Check if all items in the following tuple are the same

             def check(sampleTuple):
         return all(i == sampleTuple[0] for i in sampleTuple)

         tuple1 = (45, 45, 45, 45)
         print(check(tuple1))

Dictionary related answers

  1. Diye gaye dict me brad ki salary update karke 8500 karni hai:

     sampleDict['emp3']['salary'] = 8500
 print(sampleDict)<

  2. Ye do list hai inko dictionary me convert karna hai:

     keys = ['Ten', 'Twenty', 'Thirty']
 values = [10, 20, 30]

 sampleDict = dict(zip(keys, values))
 print(sampleDict)

  3. In 2 dictionary ko ek sath marg karo:

    dict1 = {'Ten': 10, 'Twenty': 20, 'Thirty': 30} dict2 = {'Thirty': 30, 'Fourty': 40, 'Fifty': 50}

     dict3 = dict1.copy()
 dict3.update(dict2)
 print(dict3)

  4. Is diye gaye dict mese history ki value ko show karao:

     print(sampleDict['class']['student']['marks']['history'])

  5. Diyegaye list ko as a key aur diyegaye dict ko as a value set karo:

     employees = ['Kelly', 'Emma', 'John']
 defaults = {"designation": 'Application Developer', "salary": 8000}

 resDict = dict.fromkeys(employees, defaults)
 print(resDict)

 # Individual data
 print(resDict["Kelly"])

  6. Dict me check karna hai ki kya 200 value exist karta hai ya nahi:

     sampleDict = {'a': 100, 'b': 200, 'c': 300}
 print(200 in sampleDict.values())

  7. Diye gaye dict me city ko rename karke location karna hai:

     sampleDict = {
 "name": "Kelly",
 "age":25,
 "salary": 8000,
 "city": "New york"
 }
 
 sampleDict['location'] = sampleDict.pop('city')
 print(sampleDict)

  8. Diye gaye dict me jis subject ka bhi marks sabse kam hai usko find kar ke show karna hai:

     sampleDict = {
 'Physics': 82,
 'Math': 65,
 'history': 75
 }
 print(min(sampleDict, key=sampleDict.get))

  9. Diye gaye dict mese niche bataye keys ka use kar ke new dict banao:

     sampleDict = { 
 "name": "Kelly",
 "age":25, 
 "salary": 8000, 
 "city": "New york" }

 keys = ["name", "salary"]

 newDict = {k: sampleDict[k] for k in keys}
 print(newDict)

  10. Dict mese following keys ko remove karna hai:

     sampleDict = {
 "name": "Kelly",
 "age":25,
 "salary": 8000,
 "city": "New york"
 }
 keysToRemove = ["name", "salary"]

 sampleDict = {k: sampleDict[k] for k in sampleDict.keys() - keysToRemove}
 print(sampleDict)

Set answers:

  1. Set me diye gaye list ko add karna hai:

     sampleSet = {"Yellow", "Orange", "Black"}
 sampleList = ["Blue", "Green", "Red"]
 sampleSet.update(sampleList)
 print(sampleSet)

  2. 2no set me se identical item ko find karna hai:

     set1 = {10, 20, 30, 40, 50}
 set2 = {30, 40, 50, 60, 70}

 print(set1.intersection(set2))

  3. 2no set mese unique items ko find karan hai:

     set1 = {10, 20, 30, 40, 50}
 set2 = {30, 40, 50, 60, 70}

 print(set1.union(set2))

  4. 2no set me se 1st set me jobhi item unique hai kewal unko dikhana hai:

     set1 = {10, 20, 30}
 set2 = {20, 40, 50}

 set1.difference_update(set2)
 print(set1)

  5. Diye gaye set mese 10,20,30 ek baar me hi remove karne hai:

     set1 = {10, 20, 30, 40, 50}
 set1.difference_update({10, 20, 30})
 print(set1)

  6. Diye gaye set me jo bhi number dono set me common na ho unko dikhana hai:

     set1 = {10, 20, 30, 40, 50}
 set2 = {30, 40, 50, 60, 70}

 print(set1.symmetric_difference(set2))

  7. Set 1 mese wo values ko remove karna hai jo set 2 me nahi hai:

     set1 = {10, 20, 30, 40, 50}
 set2 = {30, 40, 50, 60, 70}

 set1.intersection_update(set2)
 print(set1)

  8. 2no set me jobhi common values hai wo show karna hai:

     set1 = {10, 20, 30, 40, 50}
 set2 = {60, 70, 80, 90, 10}

 if set1.isdisjoint(set2):
 print("Two sets have no items in common")
 else:
 print("Two sets have items in common")
 print(set1.intersection(set2))

Python Input and Output Exercise with File Handling

  1. Accept two numbers from the user and calculate multiplication

             num1 = int(input("Enter first number "))
         num2 = int(input("Enter second number "))

         print("\n")
         res = num1 + num2
         print("Sum is", res)

  2. Display “My Name Is James” as “MyNameIs**James” using output formatting of a print() function

             print('My', 'Name', 'Is', 'James', sep='**')

  3. Convert decimal number to octal using print() output formatting

             print('%o,' % (8))

  4. Display float number with 2 decimal places using print()

            print('%.2f' % 458.541315)

  5. Accept list of 5 float numbers as a input from user

             floatNumbers = []
         n = int(input("Enter the list size : "))

         print("\n")
         for i in range(0, n):
         print("Enter number at location", i, ":")
         item = float(input())
         floatNumbers.append(item)
         
         print("User List is ", floatNumbers)

  6. write all file content into new file by skiping line 5 from following file

            count = 0
        with open("test.txt", "r") as fp:
        lines = fp.readlines()
        count = len(lines)
        with open("newFile.txt", "w") as fp:
        for line in lines:
                if (count == 3):
                count -= 1
                continue
                else:
                fp.write(line)
                count-=1

  7. Accept any three string from one input() call

             str1, str2, str3 = input("Enter three string").split()
         print(str1, str2, str3)

         Output:

         Enter three string jhon emma, kelly
         jhon emma, kelly

  8. You have the following data.

             quantity = 3
         totalMoney = 1000
         price = 450
         statement1 = "I have {1} dollars so I can buy {0} football for {2:.2f} dollars."
         print(statement1.format(quantity, totalMoney, price))

  9. How to check file is empty or not

             import os
         print(os.stat("test.txt").st_size == 0)

  10. Read line number 4 from the following file

             with open("test.txt", "r") as fp:
         lines = fp.readlines()
         print(lines[3])

Function answers:

  1. Given a string of odd length greater 7, return a string made of the middle three chars of a given String

             def getMiddleThreeChars(sampleStr):
                 middleIndex = int(len(sampleStr) /2)
                 print("Original String is", sampleStr)
                 middleThree = sampleStr[middleIndex-1:middleIndex+2]
                 print("Middle three chars are", middleThree)
         
         getMiddleThreeChars("JhonDipPeta")
         getMiddleThreeChars("Jasonay")

  2. Given 2 strings, s1 and s2, create a new string by appending s2 in the middle of s1

             def appendMiddle(s1, s2):
                 middleIndex = int(len(s1) /2)
                 print("Original Strings are", s1, s2)
                 middleThree = s1[:middleIndex-1:]+ s2 +s1[middleIndex-1:]
                 print("After appending new string in middle", middleThree)
         
         appendMiddle("Chrisdem", "IamNewString")

  3. arrange String characters such that lowercase letters should come first Given input String of combination of the lower and upper case arrange characters in such a way that all lowercase letters should come first.

             inputStr = "PyNaTive"
         words = inputStr.split()
         lower = []
         upper = []
         for char in inputStr:
                 if char.islower():
                         lower.append(char)
                 else:
                         upper.append(char)
         sortedString = ''.join(lower + upper)
         print("\n arranging characters giving precedence to lowercase letters:")
         print(sortedString)

  4. Count all lower case, upper case, digits, and special symbols from a given string

             def findDigitsCharsSymbols(inputString):
                 words = inputString.split()
                 charCount = 0
                 digitCount = 0
                 symbolCount = 0
                 for char in inputString:
                         if char.islower() or char.isupper():
                                 charCount+=1
                         elif char.isnumeric():
                                 digitCount+=1
                         else:
                                 symbolCount+=1
                 
                 print("Chars = ", charCount, "Digits = ", digitCount, "Symbol = ", symbolCount)
         
         inputString = "P@#yn26at^&i5ve"
         print("total counts of chars, digits,and symbols \n")

         findDigitsCharsSymbols(inputString)

  5. Given two strings, s1 and s2, create a mixed String Note: create a third-string made of the first char of s1 then the last char of s2, Next, the second char of s1 and second last char of s2, and so on. Any leftover chars go at the end of the result.

            def mixString(s1, s2):
          s2 = s2[::-1]
          lengthS1 = len(s1)
          lengthS2 = len(s2)
          length  = lengthS1 if lengthS1 > lengthS2 else lengthS2 
          resultString=""
          for i in range(length):
            if(i < lengthS1):
              resultString = resultString + s1[i]
            if(i < lengthS2):
              resultString = resultString + s2[i]

          print(resultString)

        s1 = "Abc"
        s2 = "Xyz"
        mixString(s1, s2)

  6. String characters balance Test We’ll say that a String s1 and s2 is balanced if all the chars in the string1 are there in s2. characters position doesn’t matter.

             def stringBalanceCheck(s1, s2):
           flag = True
           for char in s1:
             if char in s2:
               continue
             else:
               flag = False
           return flag

         s1 = "yn"
         s2 = "Pynative"
         flag = stringBalanceCheck(s1, s2)
         print("s1 and s2 are balanced", flag)

         s1 = "ynf"
         s2 = "Pynative"
         flag = stringBalanceCheck(s1, s2)
         print("s1 and s2 are balanced", flag)