Added tasks 3751, 3752, 3753

Author: javadev

src/main/java/g3701_3800/s3751_total_waviness_of_numbers_in_range_i/Solution.java

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+package g3701_3800.s3751_total_waviness_of_numbers_in_range_i;
+
+// #Medium #Dynamic_Programming #Math #Enumeration #Senior #Biweekly_Contest_170
+// #2026_04_26_Time_11_ms_(98.18%)_Space_42.55_MB_(97.88%)
+
+public class Solution {
+    private int countpeakValley(int num) {
+        int lastdigit = num % 10;
+        int waiviness = 0;
+        int prevcurrent = -1;
+        num = num / 10;
+        while (num > 0) {
+            if (prevcurrent == -1) {
+                prevcurrent = num % 10;
+                num = num / 10;
+                continue;
+            }
+            int currvalue = num % 10;
+            if ((prevcurrent > currvalue && prevcurrent > lastdigit)
+                    || (prevcurrent < currvalue && prevcurrent < lastdigit)) {
+                waiviness++;
+            }
+            lastdigit = prevcurrent;
+            prevcurrent = num % 10;
+            num = num / 10;
+        }
+        return waiviness;
+    }
+
+    public int totalWaviness(int num1, int num2) {
+        int ans = 0;
+        for (int i = num1; i <= num2; i++) {
+            int l = countpeakValley(i);
+            ans = ans + l;
+        }
+        return ans;
+    }
+}

src/main/java/g3701_3800/s3751_total_waviness_of_numbers_in_range_i/readme.md

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+3751\. Total Waviness of Numbers in Range I
+
+Medium
+
+You are given two integers `num1` and `num2` representing an **inclusive** range `[num1, num2]`.
+
+The **waviness** of a number is defined as the total count of its **peaks** and **valleys**:
+
+*   A digit is a **peak** if it is **strictly greater** than both of its immediate neighbors.
+*   A digit is a **valley** if it is **strictly less** than both of its immediate neighbors.
+*   The first and last digits of a number **cannot** be peaks or valleys.
+*   Any number with fewer than 3 digits has a waviness of 0.
+
+Return the total sum of waviness for all numbers in the range `[num1, num2]`.
+
+**Example 1:**
+
+**Input:** num1 = 120, num2 = 130
+
+**Output:** 3
+
+**Explanation:**
+
+In the range `[120, 130]`:
+
+*   `120`: middle digit 2 is a peak, waviness = 1.
+*   `121`: middle digit 2 is a peak, waviness = 1.
+*   `130`: middle digit 3 is a peak, waviness = 1.
+*   All other numbers in the range have a waviness of 0.
+
+Thus, total waviness is `1 + 1 + 1 = 3`.
+
+**Example 2:**
+
+**Input:** num1 = 198, num2 = 202
+
+**Output:** 3
+
+**Explanation:**
+
+In the range `[198, 202]`:
+
+*   `198`: middle digit 9 is a peak, waviness = 1.
+*   `201`: middle digit 0 is a valley, waviness = 1.
+*   `202`: middle digit 0 is a valley, waviness = 1.
+*   All other numbers in the range have a waviness of 0.
+
+Thus, total waviness is `1 + 1 + 1 = 3`.
+
+**Example 3:**
+
+**Input:** num1 = 4848, num2 = 4848
+
+**Output:** 2
+
+**Explanation:**
+
+Number `4848`: the second digit 8 is a peak, and the third digit 4 is a valley, giving a waviness of 2.
+
+**Constraints:**
+
+*   <code>1 <= num1 <= num2 <= 10<sup>5</sup></code>

src/main/java/g3701_3800/s3752_lexicographically_smallest_negated_permutation_that_sums_to_target/Solution.java

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+package g3701_3800.s3752_lexicographically_smallest_negated_permutation_that_sums_to_target;
+
+// #Medium #Array #Math #Sorting #Greedy #Two_Pointers #Staff #Biweekly_Contest_170
+// #2026_04_26_Time_3_ms_(100.00%)_Space_162.22_MB_(86.17%)
+
+public class Solution {
+    public int[] lexSmallestNegatedPerm(int n, long target) {
+        long drop = (long) n * (n + 1) / 2 - target;
+        if (drop < 0 || drop % 2 != 0) {
+            return new int[] {};
+        }
+        int[] ans = new int[n];
+        int l = 0;
+        int r = n - 1;
+        for (int i = n; i > 0; i--) {
+            int val = i;
+            if (2 * val <= drop) {
+                drop -= 2 * val;
+                ans[l++] = -val;
+            } else {
+                ans[r--] = val;
+            }
+        }
+        if (drop != 0) {
+            return new int[] {};
+        }
+        return ans;
+    }
+}

src/main/java/g3701_3800/s3752_lexicographically_smallest_negated_permutation_that_sums_to_target/readme.md

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+3752\. Lexicographically Smallest Negated Permutation that Sums to Target
+
+Medium
+
+You are given a positive integer `n` and an integer `target`.
+
+Return the **lexicographically smallest** array of integers of size `n` such that:
+
+*   The **sum** of its elements equals `target`.
+*   The **absolute values** of its elements form a **permutation** of size `n`.
+
+If no such array exists, return an empty array.
+
+A **permutation** of size `n` is a rearrangement of integers `1, 2, ..., n`.
+
+**Example 1:**
+
+**Input:** n = 3, target = 0
+
+**Output:** [-3,1,2]
+
+**Explanation:**
+
+The arrays that sum to 0 and whose absolute values form a permutation of size 3 are:
+
+*   `[-3, 1, 2]`
+*   `[-3, 2, 1]`
+*   `[-2, -1, 3]`
+*   `[-2, 3, -1]`
+*   `[-1, -2, 3]`
+*   `[-1, 3, -2]`
+*   `[1, -3, 2]`
+*   `[1, 2, -3]`
+*   `[2, -3, 1]`
+*   `[2, 1, -3]`
+*   `[3, -2, -1]`
+*   `[3, -1, -2]`
+
+The lexicographically smallest one is `[-3, 1, 2]`.
+
+**Example 2:**
+
+**Input:** n = 1, target = 10000000000
+
+**Output:** []
+
+**Explanation:**
+
+There are no arrays that sum to 10000000000 and whose absolute values form a permutation of size 1. Therefore, the answer is `[]`.
+
+**Constraints:**
+
+*   <code>1 <= n <= 10<sup>5</sup></code>
+*   <code>-10<sup>10</sup> <= target <= 10<sup>10</sup></code>

src/main/java/g3701_3800/s3753_total_waviness_of_numbers_in_range_ii/Solution.java

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+package g3701_3800.s3753_total_waviness_of_numbers_in_range_ii;
+
+// #Hard #Dynamic_Programming #Math #Senior_Staff #Biweekly_Contest_170
+// #2026_04_26_Time_52_ms_(96.83%)_Space_46.46_MB_(98.41%)
+
+public class Solution {
+    private static class Pair {
+        long count;
+        long sum;
+
+        Pair(long count, long sum) {
+            this.count = count;
+            this.sum = sum;
+        }
+    }
+
+    private char[] digits;
+    private Pair[][][][][] memo;
+    private boolean[][][][][] seen;
+
+    public long totalWaviness(long num1, long num2) {
+        return solve(num2) - solve(num1 - 1);
+    }
+
+    private long solve(long x) {
+        if (x <= 0) {
+            return 0;
+        }
+        digits = Long.toString(x).toCharArray();
+        int n = digits.length;
+        memo = new Pair[n][2][2][11][11];
+        seen = new boolean[n][2][2][11][11];
+        return dfs(0, 1, 0, 10, 10).sum;
+    }
+
+    private Pair dfs(int pos, int tight, int started, int prev2, int prev1) {
+        if (pos == digits.length) {
+            return new Pair(1, 0);
+        }
+        if (seen[pos][tight][started][prev2][prev1]) {
+            return memo[pos][tight][started][prev2][prev1];
+        }
+        seen[pos][tight][started][prev2][prev1] = true;
+        int limit = tight == 1 ? digits[pos] - '0' : 9;
+        long totalCount = 0;
+        long totalSum = 0;
+        for (int d = 0; d <= limit; d++) {
+            int nextTight = (tight == 1 && d == limit) ? 1 : 0;
+            if (started == 0 && d == 0) {
+                // still leading zeros, number not started
+                Pair nxt = dfs(pos + 1, nextTight, 0, 10, 10);
+                totalCount += nxt.count;
+                totalSum += nxt.sum;
+            } else if (started == 0) {
+                // first real digit
+                Pair nxt = dfs(pos + 1, nextTight, 1, 10, d);
+                totalCount += nxt.count;
+                totalSum += nxt.sum;
+            } else if (prev2 == 10) {
+                // second real digit
+                Pair nxt = dfs(pos + 1, nextTight, 1, prev1, d);
+                totalCount += nxt.count;
+                totalSum += nxt.sum;
+            } else {
+                // now prev1 is an interior candidate, decide if it is peak/valley
+                int add = 0;
+                if ((prev1 > prev2 && prev1 > d) || (prev1 < prev2 && prev1 < d)) {
+                    add = 1;
+                }
+                Pair nxt = dfs(pos + 1, nextTight, 1, prev1, d);
+                totalCount += nxt.count;
+                totalSum += nxt.sum + add * nxt.count;
+            }
+        }
+        memo[pos][tight][started][prev2][prev1] = new Pair(totalCount, totalSum);
+        return memo[pos][tight][started][prev2][prev1];
+    }
+}

src/main/java/g3701_3800/s3753_total_waviness_of_numbers_in_range_ii/readme.md

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+3753\. Total Waviness of Numbers in Range II
+
+Hard
+
+You are given two integers `num1` and `num2` representing an **inclusive** range `[num1, num2]`.
+
+The **waviness** of a number is defined as the total count of its **peaks** and **valleys**:
+
+*   A digit is a **peak** if it is **strictly greater** than both of its immediate neighbors.
+*   A digit is a **valley** if it is **strictly less** than both of its immediate neighbors.
+*   The first and last digits of a number **cannot** be peaks or valleys.
+*   Any number with fewer than 3 digits has a waviness of 0.
+
+Return the total sum of waviness for all numbers in the range `[num1, num2]`.
+
+**Example 1:**
+
+**Input:** num1 = 120, num2 = 130
+
+**Output:** 3
+
+**Explanation:**
+
+In the range `[120, 130]`:
+
+*   `120`: middle digit 2 is a peak, waviness = 1.
+*   `121`: middle digit 2 is a peak, waviness = 1.
+*   `130`: middle digit 3 is a peak, waviness = 1.
+*   All other numbers in the range have a waviness of 0.
+
+Thus, total waviness is `1 + 1 + 1 = 3`.
+
+**Example 2:**
+
+**Input:** num1 = 198, num2 = 202
+
+**Output:** 3
+
+**Explanation:**
+
+In the range `[198, 202]`:
+
+*   `198`: middle digit 9 is a peak, waviness = 1.
+*   `201`: middle digit 0 is a valley, waviness = 1.
+*   `202`: middle digit 0 is a valley, waviness = 1.
+*   All other numbers in the range have a waviness of 0.
+
+Thus, total waviness is `1 + 1 + 1 = 3`.
+
+**Example 3:**
+
+**Input:** num1 = 4848, num2 = 4848
+
+**Output:** 2
+
+**Explanation:**
+
+Number `4848`: the second digit 8 is a peak, and the third digit 4 is a valley, giving a waviness of 2.
+
+**Constraints:**
+
+*   <code>1 <= num1 <= num2 <= 10<sup>15</sup></code>

src/test/java/g3701_3800/s3751_total_waviness_of_numbers_in_range_i/SolutionTest.java

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+package g3701_3800.s3751_total_waviness_of_numbers_in_range_i;
+
+import static org.hamcrest.CoreMatchers.equalTo;
+import static org.hamcrest.MatcherAssert.assertThat;
+
+import org.junit.jupiter.api.Test;
+
+class SolutionTest {
+    @Test
+    void totalWaviness() {
+        assertThat(new Solution().totalWaviness(120, 130), equalTo(3));
+    }
+
+    @Test
+    void totalWaviness2() {
+        assertThat(new Solution().totalWaviness(198, 202), equalTo(3));
+    }
+
+    @Test
+    void totalWaviness3() {
+        assertThat(new Solution().totalWaviness(4848, 4848), equalTo(2));
+    }
+}

src/test/java/g3701_3800/s3752_lexicographically_smallest_negated_permutation_that_sums_to_target/SolutionTest.java

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+package g3701_3800.s3752_lexicographically_smallest_negated_permutation_that_sums_to_target;
+
+import static org.hamcrest.CoreMatchers.equalTo;
+import static org.hamcrest.MatcherAssert.assertThat;
+
+import org.junit.jupiter.api.Test;
+
+class SolutionTest {
+    @Test
+    void lexSmallestNegatedPerm() {
+        assertThat(new Solution().lexSmallestNegatedPerm(3, 0L), equalTo(new int[] {-3, 1, 2}));
+    }
+
+    @Test
+    void lexSmallestNegatedPerm2() {
+        assertThat(new Solution().lexSmallestNegatedPerm(3, 10000000000L), equalTo(new int[] {}));
+    }
+}

src/test/java/g3701_3800/s3753_total_waviness_of_numbers_in_range_ii/SolutionTest.java

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+package g3701_3800.s3753_total_waviness_of_numbers_in_range_ii;
+
+import static org.hamcrest.CoreMatchers.equalTo;
+import static org.hamcrest.MatcherAssert.assertThat;
+
+import org.junit.jupiter.api.Test;
+
+class SolutionTest {
+    @Test
+    void totalWaviness() {
+        assertThat(new Solution().totalWaviness(120L, 130L), equalTo(3L));
+    }
+
+    @Test
+    void totalWaviness2() {
+        assertThat(new Solution().totalWaviness(198L, 202L), equalTo(3L));
+    }
+
+    @Test
+    void totalWaviness3() {
+        assertThat(new Solution().totalWaviness(4848L, 4848L), equalTo(2L));
+    }
+}