Sync LeetCode submission Runtime - 0 ms (100.00%), Memory - 8.6 MB (73.56%)

Author: koralkulacoglu

LeetCode/3468-find-the-encrypted-string/README.md

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+<p>You are given a string <code>s</code> and an integer <code>k</code>. Encrypt the string using the following algorithm:</p>
+
+<ul>
+	<li>For each character <code>c</code> in <code>s</code>, replace <code>c</code> with the <code>k<sup>th</sup></code> character after <code>c</code> in the string (in a cyclic manner).</li>
+</ul>
+
+<p>Return the <em>encrypted string</em>.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">s = &quot;dart&quot;, k = 3</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">&quot;tdar&quot;</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<ul>
+	<li>For <code>i = 0</code>, the 3<sup>rd</sup> character after <code>&#39;d&#39;</code> is <code>&#39;t&#39;</code>.</li>
+	<li>For <code>i = 1</code>, the 3<sup>rd</sup> character after <code>&#39;a&#39;</code> is <code>&#39;d&#39;</code>.</li>
+	<li>For <code>i = 2</code>, the 3<sup>rd</sup> character after <code>&#39;r&#39;</code> is <code>&#39;a&#39;</code>.</li>
+	<li>For <code>i = 3</code>, the 3<sup>rd</sup> character after <code>&#39;t&#39;</code> is <code>&#39;r&#39;</code>.</li>
+</ul>
+</div>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">s = &quot;aaa&quot;, k = 1</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">&quot;aaa&quot;</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>As all the characters are the same, the encrypted string will also be the same.</p>
+</div>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= s.length &lt;= 100</code></li>
+	<li><code>1 &lt;= k &lt;= 10<sup>4</sup></code></li>
+	<li><code>s</code> consists only of lowercase English letters.</li>
+</ul>

LeetCode/3468-find-the-encrypted-string/solution.cpp

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+class Solution {
+public:
+    string getEncryptedString(string s, int k) {
+        int n = s.size();
+        string ns = s;
+        for (int i=0; i<n; i++) ns[i] = s[(i+k)%n];
+        return ns;
+    }
+};