[Merged by Bors] - feat: integral of a continuous bilinear map applied to independent random variables#38754
[Merged by Bors] - feat: integral of a continuous bilinear map applied to independent random variables#38754EtienneC30 wants to merge 21 commits into
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…alar multiplication
PR summary e6e0db9d6cImport changes for modified filesNo significant changes to the import graph Import changes for all files
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The better generalization is the following: if |
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When I started this I intended to do it for a general bilinear map but I was not satisfied because I could not drop the integrability condition as can be done with multiplication. In the end I proved a version for bilinear maps with the extra-assumption that |
| is a continuous bilinear map, then `∫ ω, B (X ω) (Y ω) ∂μ = B μ[X] μ[Y].` -/ | ||
| theorem IndepFun.integral_bilin | ||
| [NormedAddCommGroup E] [NormedSpace ℝ E] [NormedSpace 𝕜 E] [CompleteSpace E] | ||
| [SecondCountableTopology E] [MeasurableSpace E] [BorelSpace E] |
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do you really need the second countable topology here? I haven't thought about it, but since X is integrable everything should happen in a second-countable part of the space. Maybe for the proof it's better to prove this one first and then deduce the version with the f?
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I opened #39644 which proves that the identity is a.e.-strongly measurable with respect to µ.map f if f is a.e.-strongly measurable.
…p by an a.e.-strongly measurable function
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This PR/issue depends on: |
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bors r+ |
…ndom variables (#38754) If `X` and `Y` are independent then `∫ ω, X ω * Y ω ∂μ = ∫ ω, X ω ∂μ * ∫ ω, Y ω ∂μ`. We generalize this to the case of a general continuous bilinear map, and specialize it for scalar multiplication and multiplication.
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Pull request successfully merged into master. Build succeeded: |
…ndom variables (leanprover-community#38754) If `X` and `Y` are independent then `∫ ω, X ω * Y ω ∂μ = ∫ ω, X ω ∂μ * ∫ ω, Y ω ∂μ`. We generalize this to the case of a general continuous bilinear map, and specialize it for scalar multiplication and multiplication.
…ndom variables (leanprover-community#38754) If `X` and `Y` are independent then `∫ ω, X ω * Y ω ∂μ = ∫ ω, X ω ∂μ * ∫ ω, Y ω ∂μ`. We generalize this to the case of a general continuous bilinear map, and specialize it for scalar multiplication and multiplication.
…ndom variables (leanprover-community#38754) If `X` and `Y` are independent then `∫ ω, X ω * Y ω ∂μ = ∫ ω, X ω ∂μ * ∫ ω, Y ω ∂μ`. We generalize this to the case of a general continuous bilinear map, and specialize it for scalar multiplication and multiplication.
If
XandYare independent then∫ ω, X ω * Y ω ∂μ = ∫ ω, X ω ∂μ * ∫ ω, Y ω ∂μ.We generalize this to the case of a general continuous bilinear map, and specialize it for scalar multiplication and multiplication.