[Merged by Bors] - feat(LinearAlgebra/Matrix/Adjugate): M.det = 0 if M *ᵥ v = 0 where v contains a non-zero-divisor#39642
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…e `v` contains a non-zero-divisor
PR summary a7cb828610Import changes for modified filesNo significant changes to the import graph Import changes for all files
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mathlib-bors Bot
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…e `v` contains a non-zero-divisor (#39642) The non-zero-divisor requirement is necessary since otherwise we could take any `a * b = 0` with `a ≠ 0 ∧ b ≠ 0` and consider the 1x1 matrix formed by `a` and the single-entry vector formed by `b`. Then `M.det = a ≠ 0` and `M *ᵥ v = a * b = 0`.
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M.det = 0 if M *ᵥ v = 0 where v contains a non-zero-divisorM.det = 0 if M *ᵥ v = 0 where v contains a non-zero-divisor
RaggedR
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May 22, 2026
…e `v` contains a non-zero-divisor (leanprover-community#39642) The non-zero-divisor requirement is necessary since otherwise we could take any `a * b = 0` with `a ≠ 0 ∧ b ≠ 0` and consider the 1x1 matrix formed by `a` and the single-entry vector formed by `b`. Then `M.det = a ≠ 0` and `M *ᵥ v = a * b = 0`.
b-mehta
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Jun 2, 2026
…e `v` contains a non-zero-divisor (leanprover-community#39642) The non-zero-divisor requirement is necessary since otherwise we could take any `a * b = 0` with `a ≠ 0 ∧ b ≠ 0` and consider the 1x1 matrix formed by `a` and the single-entry vector formed by `b`. Then `M.det = a ≠ 0` and `M *ᵥ v = a * b = 0`.
Bergschaf
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Jun 3, 2026
…e `v` contains a non-zero-divisor (leanprover-community#39642) The non-zero-divisor requirement is necessary since otherwise we could take any `a * b = 0` with `a ≠ 0 ∧ b ≠ 0` and consider the 1x1 matrix formed by `a` and the single-entry vector formed by `b`. Then `M.det = a ≠ 0` and `M *ᵥ v = a * b = 0`.
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The non-zero-divisor requirement is necessary since otherwise we could take any
a * b = 0witha ≠ 0 ∧ b ≠ 0and consider the 1x1 matrix formed byaand the single-entry vector formed byb. ThenM.det = a ≠ 0andM *ᵥ v = a * b = 0.The natural language proof is by ChatGPT 5.5; the rest is entirely human-made: the code, the counterexample, and also the idea for the statement.