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for (num = 101; num <= 200; num = num + 2)//Circulating in the even number is not a prime number, add 2 at a time
{
for (div = 2; div <= sqrt(num); div++)//N a number of factors can't more than n, but if we know after a factor a number n, another factor b (b = n/a) also knew, therefore enumerate a number n only when the factor of enumeration from 2 to SQRT (n)