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Clean up get_histogram_bucket() #753
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
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@@ -3129,13 +3129,13 @@ histogram_bucket_timings(int index, double *b_start, double *b_end) | |
| static int | ||
| get_histogram_bucket(double q_time) | ||
| { | ||
| for (int index = 0; index < hist_bucket_count_total - 1; index++) | ||
| for (int index = 0; index < hist_bucket_count_total; index++) | ||
| { | ||
| if (q_time >= hist_bucket_timings[index].start && q_time <= hist_bucket_timings[index].end) | ||
| if (q_time <= hist_bucket_timings[index].end) | ||
| return index; | ||
| } | ||
|
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||
| /* Given the uppermost bound is inifity we should never reach this */ | ||
| /* Given the uppermost bound is infinity we should never reach this */ | ||
|
Contributor
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. The cleanup looks good, but is this comment always true? But it can be also HISTOGRAM_MAX_TIME, in which case we don't add infinity. |
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| return hist_bucket_count_total - 1; | ||
| } | ||
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I thought it was done intentionally. We don't check last bucket as it's always has open end bound and we will return this bucket as last option on line 3139.