Fix HLSLParser failing on parenthesized expressions in declarations

The parser rejected valid HLSL like `float2 var = (float2(x,y)) * scalar`
with "expected ';'" errors. When parsing a parenthesized expression, the
loop would break before consuming the closing paren, so subsequent binary
operators were never seen.

Moves end-char consumption into the else block and checks for operators
after consuming the paren, continuing the loop if one is found.

Fixes #940

Author: revmischa

vendor/hlslparser/src/HLSLParser.cpp

@@ -2283,6 +2283,20 @@ bool HLSLParser::ParseBinaryExpression(int priority, HLSLExpression*& expression
         }
         else
         {
+            // Before breaking, consume end char if needed and check for more operators
+            if( needsExpressionEndChar != 0 )
+            {
+                if( !Expect(needsExpressionEndChar) )
+                    return false;
+                needsExpressionEndChar = 0;
+
+                // After consuming end char, check if there's a binary operator to continue
+                if (AcceptBinaryOperator(priority, binaryOp))
+                {
+                    acceptBinaryOp = true;
+                    continue;
+                }
+            }
             break;
         }