Create python check_instagram.py

import requests

def check_username(username):
    url = f"https://www.instagram.com/{username}/"
    response = requests.get(url)
    if response.status_code == 404:
        return True
    return False

# توليد يوزرات عشوائية (مثال)
import random
import string

def generate_usernames(length=4, count=50):
    usernames = set()
    while len(usernames) < count:
        username = ''.join(random.choices(string.ascii_lowercase + string.digits, k=length))
        usernames.add(username)
    return list(usernames)

# تحقق من التوفر
usernames = generate_usernames()
available = []

for name in usernames:
    try:
        if check_username(name):
            print(f"[✓] Available: {name}")
            available.append(name)
        else:
            print(f"[X] Taken: {name}")
    except Exception as e:
        print(f"Error checking {name}: {e}")

# عرض المتاحين
print("\nAvailable usernames:")
print(available)

Author: zainzain83828

python check_instagram.py

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