How can I move the Start menu to the left by a bit?

[cyb233]

I tried this target, but it doesn't work correctly. After moving it, the left side of the view is invisible.

{
  "theme": "TranslucentStartMenu",
  "disableNewStartMenuLayout": "disableNewLayoutKeepPhoneLink",
  "controlStyles[0].target": "StartDocked.StartSizingFrame",
  "controlStyles[0].styles[0]": "RenderTransform:=<TranslateTransform X=\"-255\" Y=\"0\" />",
  "webContentStyles[0].target": "",
  "webContentStyles[0].styles[0]": "",
  "webContentCustomJs": "",
  "styleConstants[0]": "",
  "resourceVariables[0].variableKey": "",
  "resourceVariables[0].value": "",
  "themeResourceVariables[0]": ""
}

[m417z]

You can try this mod: https://windhawk.net/mods/shell-flyout-positions

[cyb233]

It works perfectly! Thanks for the help.

[cyb233]

BTW, I use Windows 11 Taskbar Styler and move taskbar left, but right click menu not move, how to fix it?
The config now is:

{
  "theme": "DockLike",
  "controlStyles[0].target": "Taskbar.TaskbarFrame#TaskbarFrame > Grid#RootGrid",
  "controlStyles[0].styles[0]": "Background:=<AcrylicBrush TintColor=\"Transparent\" TintOpacity=\"0.5\" TintLuminosityOpacity=\"0.8\" Opacity=\"0.5\"/>",
  "styleConstants[0]": "",
  "resourceVariables[0].variableKey": "",
  "resourceVariables[0].value": "",
  "controlStyles[1].styles[0]": "Background:=<AcrylicBrush TintColor=\"Transparent\" TintOpacity=\"0.5\" TintLuminosityOpacity=\"0.8\" Opacity=\"0.5\"/>",
  "controlStyles[1].target": "Grid#SystemTrayFrameGrid",
  "controlStyles[2].target": "Windows.UI.Xaml.Controls.Grid#ModalRootGrid > Windows.UI.Xaml.Controls.Border#BackgroundElement",
  "controlStyles[2].styles[0]": "Background:=<AcrylicBrush TintColor=\"Transparent\" TintOpacity=\"0.5\" TintLuminosityOpacity=\"0.8\" Opacity=\"0.5\"/>",
  "controlStyles[0].styles[1]": "RenderTransform:=<TranslateTransform X=\"-255\" Y=\"0\" />",
  "themeResourceVariables[0]": "",
  "xamlDiagnosticsHandling": "alert"
}

@m417z