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Solution.java
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38 lines (28 loc) · 1.07 KB
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/*
@lc id : 107 Binary Tree Level Order Traversal II
Author : Rohit
Date : 02/07/2020
*/
class Solution {
public List<List<Integer>> levelOrderBottom(TreeNode root) {
if(root == null)
return new ArrayList<List<Integer>>();
Queue<TreeNode> queue = new LinkedList<TreeNode>();
List<List<Integer>> levelOrderTraversal = new ArrayList<List<Integer>>();
queue.add(root);
while(!queue.isEmpty()){
int qSize = queue.size();
List<Integer> currLevel = new ArrayList<Integer>();
for(int i = 0; i < qSize; i++){
TreeNode currNode = queue.remove();
currLevel.add(currNode.val);
if(currNode.left != null)
queue.add(currNode.left);
if(currNode.right != null)
queue.add(currNode.right);
}
levelOrderTraversal.add(0, currLevel);
}
return levelOrderTraversal;
}
}