Feature description
Hi,
I have a collection of 500 files and I need to run a sanity check. However I cannot find anything like:
import ROOT
status = ROOT.TFile.check_health('file.root')
if status != 0:
raise ValueError('message here')
How is the user supposed to know if a file has problems among hundreds?
Alternatives considered
No response
Additional context
No response
Feature description
Hi,
I have a collection of 500 files and I need to run a sanity check. However I cannot find anything like:
How is the user supposed to know if a file has problems among hundreds?
Alternatives considered
No response
Additional context
No response