Factorial digit sum $ n! $ means $ n × (n − 1) × ... × 3 × 2 × 1 $ For example, $ 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800 $, and the sum of the digits in the number $ 10! $ is $ 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27 $. Find the sum of the digits in the number $ 100! $