refactor: convert static to dynamic allocation in benchmark1 and benchmark2

Signed-off-by: Yohan Park <88149844+yohan9569@users.noreply.github.com>

Author: yohan9569

lib/node_modules/@stdlib/blas/base/dsdot/benchmark/c/benchmark.length.c

@@ -96,12 +96,14 @@ static float rand_float( void ) {
 */
 static double benchmark1( int iterations, int len ) {
 	double elapsed;
-	float x[ len ];
-	float y[ len ];
+	float *x;
+	float *y;
 	double z;
 	double t;
 	int i;
 
+	x = (float *) malloc( len * sizeof( float ) );
+	y = (float *) malloc( len * sizeof( float ) );
 	for ( i = 0; i < len; i++ ) {
 		x[ i ] = ( rand_float()*20000.0f ) - 10000.0f;
 		y[ i ] = ( rand_float()*20000.0f ) - 10000.0f;
@@ -119,6 +121,9 @@ static double benchmark1( int iterations, int len ) {
 	if ( z != z ) {
 		printf( "should not return NaN\n" );
 	}
+
+	free( x );
+	free( y );
 	return elapsed;
 }
 
@@ -131,12 +136,14 @@ static double benchmark1( int iterations, int len ) {
 */
 static double benchmark2( int iterations, int len ) {
 	double elapsed;
-	float x[ len ];
-	float y[ len ];
+	float *x;
+	float *y;
 	double z;
 	double t;
 	int i;
 
+	x = (float *) malloc( len * sizeof( float ) );
+	y = (float *) malloc( len * sizeof( float ) );
 	for ( i = 0; i < len; i++ ) {
 		x[ i ] = ( rand_float()*20000.0f ) - 10000.0f;
 		y[ i ] = ( rand_float()*20000.0f ) - 10000.0f;
@@ -154,6 +161,8 @@ static double benchmark2( int iterations, int len ) {
 	if ( z != z ) {
 		printf( "should not return NaN\n" );
 	}
+	free( x );
+	free( y );
 	return elapsed;
 }