将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例:
输入:1->2->4, 1->3->4 输出:1->1->2->3->4->4
题目标签:Linked List
题目链接:LeetCode / LeetCode中国
| Language | Runtime | Memory |
|---|---|---|
| cpp | 12 ms | 1.9 MB |
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
ListNode* res = new ListNode(-1);
ListNode* r = res;
ListNode* p = l1;
ListNode* q = l2;
while (p && q) {
if (p->val < q->val) {
r->next = new ListNode(p->val);
p = p->next;
} else {
r->next = new ListNode(q->val);
q = q->next;
}
r = r->next;
}
while (p) {
r->next = new ListNode(p->val);
p = p->next;
r = r->next;
}
while (q) {
r->next = new ListNode(q->val);
q = q->next;
r = r->next;
}
res = res->next;
return res;
}
};