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// Time Complexity : O(nlog n)
// Space Complexity : O(n) worst case
// Your code here along with comments explaining your approach
/*
* The idea is to split and sort left and right sub arrays recursively first and then eventually merge
* using 2 pointers making sure to pick smaller element each time, placing it in main array.
* */
class MergeSort
{
// Merges two subarrays of arr[].
// First subarray is arr[l..m]
// Second subarray is arr[m+1..r]
void merge(int arr[], int l, int m, int r)
{
//Your code here
int n1 = m - l + 1;
int n2 = r - m;
int[] N1 = new int[n1];
int[] N2 = new int[n2];
for(int i = 0 ; i < n1 ; i++)
N1[i] = arr[l + i];
for(int j = 0 ; j < n2 ; j++)
N2[j] = arr[m + 1 + j];
int i = 0, j = 0 , k = l;
while(i < n1 && j < n2) {
if(N1[i] < N2[j]) {
arr[k++] = N1[i++];
}
else
arr[k++] = N2[j++];
}
while(i < n1)
arr[k++] = N1[i++];
while(j < n2)
arr[k++] = N2[j++];
}
// Main function that sorts arr[l..r] using
// merge()
void sort(int arr[], int l, int r)
{
//Write your code here
//Call mergeSort from here
if(l < r) {
int m = l + (r - l) / 2;
sort(arr, l, m);
sort(arr, m + 1, r);
merge(arr, l , m , r);
}
}
/* A utility function to print array of size n */
static void printArray(int arr[])
{
int n = arr.length;
for (int i=0; i<n; ++i)
System.out.print(arr[i] + " ");
System.out.println();
}
// Driver method
public static void main(String args[])
{
int arr[] = {12, 11, 13, 5, 6, 7};
System.out.println("Given Array");
printArray(arr);
MergeSort ob = new MergeSort();
ob.sort(arr, 0, arr.length-1);
System.out.println("\nSorted array");
printArray(arr);
}
}